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In a triangle, with usual notations, the...

In a triangle, with usual notations, the length of the bisector of angle A is

A

`(2bc cosA/2)/(b+c)`

B

`(2bc sinA/2)/(b+c)`

C

`(abc " cosec " A/2)/(2R(b+c))`

D

`(2Delta)/(b+c) " cosec " A/2`

Text Solution

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The correct Answer is:
To find the length of the bisector of angle A in a triangle ABC, we can use the formula for the length of an angle bisector. The formula is given by: \[ l_a = \frac{2bc}{b+c} \cdot \cos\left(\frac{A}{2}\right) \] where: - \( l_a \) is the length of the angle bisector from vertex A, - \( b \) and \( c \) are the lengths of the sides opposite to vertices B and C respectively, - \( A \) is the angle at vertex A. ### Step-by-Step Solution: 1. **Identify the sides and angle**: In triangle ABC, identify the lengths of sides \( b \) and \( c \) opposite to angles B and C respectively, and the angle \( A \) at vertex A. 2. **Apply the angle bisector formula**: Use the formula for the length of the angle bisector: \[ l_a = \frac{2bc}{b+c} \cdot \cos\left(\frac{A}{2}\right) \] 3. **Calculate \( \cos\left(\frac{A}{2}\right) \)**: If necessary, calculate \( \cos\left(\frac{A}{2}\right) \) using trigonometric identities or tables. 4. **Substitute the values**: Substitute the values of \( b \), \( c \), and \( \cos\left(\frac{A}{2}\right) \) into the formula. 5. **Simplify the expression**: Simplify the expression to find the length of the angle bisector \( l_a \). ### Example Calculation: Assuming \( A = 60^\circ \), \( b = 5 \), and \( c = 7 \): 1. Calculate \( \cos\left(\frac{60^\circ}{2}\right) = \cos(30^\circ) = \frac{\sqrt{3}}{2} \). 2. Substitute into the formula: \[ l_a = \frac{2 \cdot 5 \cdot 7}{5 + 7} \cdot \frac{\sqrt{3}}{2} \] 3. Simplify: \[ l_a = \frac{70}{12} \cdot \frac{\sqrt{3}}{2} = \frac{35\sqrt{3}}{12} \] ### Final Result: The length of the bisector of angle A is \( \frac{35\sqrt{3}}{12} \).
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