Home
Class 12
CHEMISTRY
6.02xx10^(20) molecules of urea are pres...

`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:

A

`0.001M`

B

`0.01M`

C

`0.02M`

D

`0.1M`.

Text Solution

AI Generated Solution

The correct Answer is:
To find the concentration of the urea solution, we need to follow these steps: 1. **Convert the volume of the solution from milliliters to liters.** 2. **Calculate the number of moles of urea using Avogadro's number.** 3. **Determine the molar concentration using the formula for molarity.** Let's go through each step in detail: ### Step 1: Convert the volume of the solution from milliliters to liters The given volume of the solution is 100 mL. We need to convert this to liters. \[ 100 \, \text{mL} = 100 \times 10^{-3} \, \text{L} = 0.1 \, \text{L} \] ### Step 2: Calculate the number of moles of urea We are given the number of molecules of urea as \( 6.02 \times 10^{20} \). To find the number of moles, we use Avogadro's number, which is \( 6.022 \times 10^{23} \) molecules per mole. \[ \text{Number of moles} = \frac{\text{Number of molecules}}{\text{Avogadro's number}} \] \[ \text{Number of moles} = \frac{6.02 \times 10^{20}}{6.022 \times 10^{23}} \] \[ \text{Number of moles} = \frac{6.02}{6.022} \times 10^{20 - 23} \] \[ \text{Number of moles} \approx 1 \times 10^{-3} \] ### Step 3: Determine the molar concentration Molar concentration (M) is given by the formula: \[ \text{Molarity} = \frac{\text{Number of moles of solute}}{\text{Volume of solution in liters}} \] From Step 1, the volume of the solution is \( 0.1 \, \text{L} \). From Step 2, the number of moles of urea is \( 1 \times 10^{-3} \). \[ \text{Molarity} = \frac{1 \times 10^{-3}}{0.1} \] \[ \text{Molarity} = 1 \times 10^{-2} \] \[ \text{Molarity} = 0.01 \, \text{M} \] Therefore, the concentration of the urea solution is \( 0.01 \, \text{M} \).

To find the concentration of the urea solution, we need to follow these steps: 1. **Convert the volume of the solution from milliliters to liters.** 2. **Calculate the number of moles of urea using Avogadro's number.** 3. **Determine the molar concentration using the formula for molarity.** Let's go through each step in detail: ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOLUTIONS

    RESONANCE ENGLISH|Exercise EXERCISE-3(PART-3)|30 Videos
  • SOLUTIONS

    RESONANCE ENGLISH|Exercise Advabced Level Problems (PART-1)|71 Videos
  • SOLUTIONS

    RESONANCE ENGLISH|Exercise EXERCISE-3(PART-1)|14 Videos
  • SOLUTION AND COLLIGATIVE PROPERTIES

    RESONANCE ENGLISH|Exercise PHYSICAL CHEMITRY (SOLUTION & COLLIGATIVE PROPERTIES)|52 Videos
  • STEREOISOMERISM

    RESONANCE ENGLISH|Exercise EXERCISE (PART III : PRACTICE TEST-2 (IIT-JEE (ADVANCED PATTERN))|23 Videos

Similar Questions

Explore conceptually related problems

6.02 xx 10^(20) molecules of urea are present in 100 mL of its solution. The concentration of urea solution is:

6.02xx10^(23) molecules of urea are present in 100 ml of its solution. The concentration of urea solution is -

6.02xx10^(20) molecules of urea are present in 100 ml of its solution. The concentration of solution is :

6.02 xx 10^(21) molecules of urea are present in 100ml of its solution. The concentration of urea solution is

6.02 xx 10^(21) molecules of urea are present in 1000ml of its solution. The concentration of urea solution is

6.025 xx 10^(20) molecules of acetic acid are present in 500 ml of its solution. The concentration of solution is

0.001 moles of a compound is present in 100 mL of its solution. The concentration of solution is:

(3.011 x 10^23) molecules of sugar are present in 200 mL of its solution. The molarity of solution is

500 mL of a glucose solution contains 6.02 xx 10^(22) molecules. The concentration of the solution is :

An aqueous solution of 0.01 m KCl cause the same elevation in boiling point as an aqueous solution of urea. The concentration of urea solution is :