Home
Class 11
CHEMISTRY
The equilibrium constant (K(p)) for the ...

The equilibrium constant `(K_(p))` for the reaction `PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g)` is 1.6. If the volume of the container is reduced to one half its original volume, the value of `K_(p)` for the reaction at the same temperature will be

A

`32

B

`64`

C

`16`

D

`4`

Text Solution

Verified by Experts

The correct Answer is:
C
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Exercise-2 (Part-2)|22 Videos

  • CHEMICAL EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Exercise-2 (Part-3)|33 Videos

  • CHEMICAL EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Exercise-1 (Part-2)|87 Videos

  • CHEMICAL BONDING

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Fundamental Concept )|6 Videos

  • D & F-BLOCK ELEMENTS & THEIR IMPORTANT COMPOUNDS

    RESONANCE ENGLISH|Exercise Match the column|1 Videos

Similar Questions

Explore conceptually related problems

The equilibrium constant (K_(p)) for the reaction, PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)) is 16 . If the volume of the container is reduced to half of its original volume, the value of K_(p) for the reaction at the same temperature will be:

Unit of equilibrium constant K_p for the reaction PCl_5(g) hArr PCl_3(g)+ Cl_2(g) is

Knowledge Check

  • For the reaction : PCl_(5) (g) rarrPCl_(3) (g) +Cl_(2)(g) :

    A
    (a) Equal volumes of `PCl_(5),PCl_(3)andCl_(2)` are present.
    B
    (b) Equal masses of `PCl_(5),PCl_(3)andCl_(2)` are present.
    C
    (c) The concentrations of `PCl_(5),PCl_(3)andCl_(2)` become constant.
    D
    (d) Reaction stops

    • Similar Questions

    Explore conceptually related problems

    For the reaction : PCl_(5) (g) rarrPCl_(3) (g) +Cl_(2)(g) :

    For the reaction PCl_(5)(g) rightarrow PCl_(3)(g) + Cl_(2)(g)

    The equilbrium constant of the reaction H_(2)(g)+I_(2)(g)hArr 2HI(g) is 50. If the volume of the container is reduced to half of its original value, the value of equilibrium constant will be

    The K_(c) for H_(2(g)) + I_(2(g))hArr2HI_(g) is 64. If the volume of the container is reduced to one-half of its original volume, the value of the equilibrium constant will be

    The equilibrium constant K_(p) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) changes if:

    For the reaction PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g) the forward reaction at constant temperature is favoured by

    For PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g), write the expression of K_(c)

    Home
    Profile