Home
Class 12
PHYSICS
A Carnot’s engine operates with an effic...

A Carnot’s engine operates with an efficiency of 40% with its sink at `27^(@)C.` With an aim to increase the efficiency to 50 %, the amount of increase in temperature of the source is……….K.

Text Solution

Verified by Experts

The correct Answer is:
100
`eta=1 - (T_(2))/(T_(1))implies 0.4 =1 - (300)/(T_(1))therefore T _(1)=500K`
Again, `0.5=1- (300)/( 500+ Delta T _(1)) implies 0.5 = (300)/(500+ Delta T_(1))`
`implies 500+ Delta T_(1) = 600 " " Delta T_(1) =100 K`
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISON TEST-23

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|1 Videos

  • JEE Main Revision Test-9 | JEE-2020

    VMC MODULES ENGLISH|Exercise PHYSICS SECTION 2|5 Videos

  • KINEMATICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise JEE Advanced (archive)|14 Videos

Similar Questions

Explore conceptually related problems

A carnot engine has efficiency of 50% when its sink is at 227^(@)C . What is the temperature of source

The efficiency of Carnot's enegine is 50% . The temperature of its sink is 7^(@)C . To increase its efficiency to 70% . What is the increase in temperature of the source?

A carnot engine has efficiency of 80%. If its sink is at 127^(@)C , the find the temperature of source.

A carnot engine has efficiency of 80%. If its sink is at 127^(@)C , the find the temperature of source.

A carnot engine has efficiency of 60%. If the source is at 527^(@)C , then find the temperature of sink.

An engine has an efficiency of 0.25 when temperature of sink is reduced by 58^(@)C , If its efficiency is doubled, then the temperature of the source is

A carnot engine whose sink is at 290 K has an efficiency of 30%. By how much the temperature of the source be increased to have its efficiency equal to 50%, keeping sink temperature constant

A Carnot engine has an efficiency of 1//6 . When the temperature of the sink is reduced by 62^(@)C , its efficiency is doubled. The temperature of the source and the sink are, respectively.

A beat engine work on a Cannot cycle with the heat sink in the temperature of 27^(@)C . IF the efficiency is 20%, then the temperature (in Kelvin) of the heat source will be

A Carnot engine whose low-temperature reservoir is at 350 K has efficiency of 50%. It is desired to increase this to 60%. It the temperature of the low-temperature reservoir remains constant, then the temperature reservoir remains constant, then the temperature of the high-temperature reservoir must be increased by how many degrees?

Knowledge Check

  • An engine has an efficiency of 0.25 when temperature of sink is reduced by 58^(@)C , If its efficiency is doubled, then the temperature of the source is

    A
    `150 ^(@)C`
    B
    `222 ^(@)C`
    C
    `242 ^(@)C`
    D
    `232 ^(@)C`

  • A beat engine work on a Cannot cycle with the heat sink in the temperature of 27^(@)C . IF the efficiency is 20%, then the temperature (in Kelvin) of the heat source will be

    A
    375
    B
    300
    C
    270
    D
    150