Home
Class 12
CHEMISTRY
CsBr has bcc stucture with edge length 4...

`CsBr` has bcc stucture with edge length `4.3` A .The shortest interionic distance in between Cs and Br is

A

3.72 Å

B

1.86 Å

C

7.44 Å

D

4.3Å

Text Solution

AI Generated Solution

To find the shortest interionic distance between cesium (Cs) and bromine (Br) in cesium bromide (CsBr) with a body-centered cubic (BCC) structure and an edge length of 4.3 Å, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Structure**: CsBr has a body-centered cubic (BCC) structure. In a BCC lattice, there is one atom at each corner of the cube and one atom at the center of the cube. 2. **Understand the Relationship Between Edge Length and Atomic Radius**: ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THE SOLID STATE

    VMC MODULES ENGLISH|Exercise JEE Advance ( Archive )|27 Videos

  • THE SOLID STATE

    VMC MODULES ENGLISH|Exercise FUNDAMENTAL|50 Videos

  • THE SOLID STATE

    VMC MODULES ENGLISH|Exercise LEVEL-2 (Numerical Value Type for JEE Main )|15 Videos

  • SURFACE CHEMISTRY

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE|9 Videos

  • THEORY OF SOLUTIONS

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|31 Videos

Similar Questions

Explore conceptually related problems

CsBr has bcc like structures with edge length 4.3Å . The shortest inter ionic distance in between Cs^(+) and Br^(-) is:

CsBr has bcc structure with edge length of 43 pm . The shortest interionic distance between cation and anion is

CsBr has bcc lattice with the edge length 9.4 Å, the shortest inter- ionic distance in between Cs^(+) & Br^(-) is:

In a CsCl structure, if edge length is a, then distance between one Cs atom and one Cl atoms is

CsCl has cubic structure. Its density is 3.99 g cm^(-3) . What is the distance between Cs^(o+) and Cl^(Θ) ions? (Atomic mass of Cs = 133 )

CsCl has bc c arrangement and its unit cell edge length is 400 pm. Calculate the interionic distance in CsCl .

A compound AB crystallizes in bcc lattice with unit edge length of 380 pm. Calculate (i)The distance between oppositely charged ions in the lattice. (ii)Radius of A^+ if radius of B is 175 pm

Metallic gold crystallises in face centred cubic lattice with edge-length 4.07Å . Closest distance between gold atoms is:

Metallic gold crystallises in face centred cubic lattice with edge-length 4.07Å . Closest distance between gold atoms is:

Two circles have an external tangent with length 36 cm. The shortest distance between these circles is 14 cm. If the radius of the longer circle is 4 times the radius of the smaller circle then the radius of the larger circle in cms is

Home
Profile