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Molality of 1 M NaNO3 solution (Density ...

Molality of 1 M `NaNO_3` solution (Density of solution is `1.25 g Ml^(-1)`and mol. wt. of `NaNO_3 = 85 g mol^(-1)` ) is

A

1.286 m

B

4.44 m

C

0.858 m

D

none of these.

Text Solution

Verified by Experts

The correct Answer is:
C
`rho=1.25 g mL^(-1), M_(NaNO_3) = 85 g mol^(-1), Molarity = 1`
`M 1/m =rho/M (M_(NaNO_3))/1000 implies 1/m = (1.25)/1 - 85/1000 = 1.25 -0.085 = 1.165 " in " = 0.858 2`.
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Knowledge Check

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