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The osmotic pressure of a urea solution ...

The osmotic pressure of a urea solution is 500 mm Hg at `10^@C`. The solution is diluted and its temperature is raised to `25^@C`. It is now found that osmotic pressure of the solution is reduced to 105.3 mm Hg. The extent of dilution of the solution is

A

3 times

B

4 times

C

5 times

D

6 times.

Text Solution

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The correct Answer is:
C
5 times
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The osmotic pressure of a dilute solution is given by

Osmotic pressure of urea solution is 56.6 mm Hg at a temperature of 10^(@)C . The solution is diluted and the temperature is raised to 40^(@) C such that the osmotic pressure is found to be 31.3 mm Hg . The extent of dilution will be :

The osmotic pressure of urea solution is 500 mm at 10^(@)C . The solution is diluted and the temperature raised to 25^(@)C , when the osmotic pressure is found to be 105.3 mm . Find the extend if dilution.

The osmotic pressure of a dilute solution increases when

Knowledge Check

  • The osmotic pressure of a dilute solution is given by

    A
    `P=P_(o)x`
    B
    `pi V=nRT`
    C
    `Delta P=P_(o)N_(2)`
    D
    `(Delta P)/(P_(o))=(P_(o)-P)/(P_(o))`

  • The osmotic pressure of a dilute solution is given by

    A
    `P=P_(0)xxN_(1)`
    B
    `piV=nRT`
    C
    `DeltaP=P_(0)N_(2)`
    D
    `(DeltaP)/(P^(@))=(P^(@)-P_(s))/P^(@)`

  • Osmotic pressure of urea solution is 56.6 mm Hg at a temperature of 10^(@)C . The solution is diluted and the temperature is raised to 40^(@) C such that the osmotic pressure is found to be 31.3 mm Hg . The extent of dilution will be :

    A
    `V_("final") = 10 V_("initial")`
    B
    `V_("final") = 2 V_("initial")`
    C
    `2V_("final ") = 3V_("initial")`
    D
    `V_("final") = 20 V_("initial")`
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