From the data given below, calculate the average rate of the reaction :
` C_4 H_9 Cl +H_2 O to C_4 H_9 OH +HCl` during different intervals of time.

Answer

Rate in mol `L^(-1) s^(-1) xx 10^4`
`r_(50 ) - 1.90 ,r_(100)= 1.70, r_(150) = 1.58 ; r_(200) = 1.40`
` r_(300) = 1.22 =r_(400) = 1.10 , r_(700) = 1.04 , r_(800 ) = 0.4`

Explanation

`R_(50) = ( 0.100 -0.0905 )/( 50-0 ) = 1.9 xx 10^(-4) mol L^(-1) s^(-1)`
` r_(100) = ( 0.0905 - 0.0820 )/( 100-50 ) = 1.7 xx 10^(-4) mol L^(-1) s^(-1)`
` r_(150 ) = ( 0.0820 - 0.0741 )/( 150-100 ) `
`= 1.58 xx 10^(-4) mol L^(-1) s^(-1) ` and so on .