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From the data given below, calculate the...

From the data given below, calculate the average rate of the reaction :
` C_4 H_9 Cl +H_2 O to C_4 H_9 OH +HCl` during different intervals of time.

Text Solution

Verified by Experts

The correct Answer is:
Rate in mol `L^(-1) s^(-1) xx 10^4`
`r_(50 ) - 1.90 ,r_(100)= 1.70, r_(150) = 1.58 ; r_(200) = 1.40`
` r_(300) = 1.22 =r_(400) = 1.10 , r_(700) = 1.04 , r_(800 ) = 0.4`
`R_(50) = ( 0.100 -0.0905 )/( 50-0 ) = 1.9 xx 10^(-4) mol L^(-1) s^(-1)`
` r_(100) = ( 0.0905 - 0.0820 )/( 100-50 ) = 1.7 xx 10^(-4) mol L^(-1) s^(-1)`
` r_(150 ) = ( 0.0820 - 0.0741 )/( 150-100 ) `
`= 1.58 xx 10^(-4) mol L^(-1) s^(-1) ` and so on .
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From the concetration of C_(4)H_(9)Cl (butyl chloride) at different times given below, calculate the average rate of reaction: C_(4)H_(9)Cl+H_(2)O rarr C_(4)H_(9)OH+HCl during different intervals of time. |{:([C_(4)H_(9)Cl] (mol L^(-1)),t (s)),(0.100,0),(0.0905,50),(0.0820,100),(0.0741,150),(0.0671,200),(0.0549,300),(0.0439,400),(0.0210,700),(0.017,800):}|

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Knowledge Check

  • Major product of the given reaction is : H_2 C =CH - CH_2 - underset(C Cl_4) overset("HI (excess)")to

    A
    `CH_3 - underset(I ) underset(| ) CH- underset(I) underset(|)CH_2`
    B
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    C
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    D
    `I-CH_2 - CdH_2 -CH_2 -I`

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