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A sugar syrup of weight 214.2g contains ...

A sugar syrup of weight 214.2g contains 34.2g of sugar `(C_(12)H_(22)O_(11))` . Calculate (i) Molality and (ii) Mole fraction of sugar in syrup.

Text Solution

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The correct Answer is:
`x_("sugar")= 0.01 `
Mass of Solution = 214 . 2 g
Mass of sugar `(C_(12) H_(22) O_(11)) = 34 . 2 g`
`:.` Mass of Water = 214 . 2 - 34 . 2 = 180 g
`n_("water") = (180)/(18 g mol^(-1)) = 10 ` mol
`n_("sugar") = ( 34 . 2 g)/( 342 g mol^(-1)) ` = 0 . 1 mol
(Molar mass of `C_(12) H_(22) O_(11) = 342 g mol^(-1)`)
`x_("sugar") = (n_("sugar"))/( n_("sugar") + n_("water"))`
`= (0 . 10 )/( 0 . 10 + 10 ) = (0 . 10)/( 10 . 10) = 0 . 01 `
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