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10g of non-volatile solute when dissolve...

10g of non-volatile solute when dissolved in 100g of benzene raises its boiling point by `1^@` C. What is the molecular mass of the solute. (`k_b` for benzene=2.53 K kg `mol^-1`)

Text Solution

Verified by Experts

Here we are given
`w_(B) = 10g, w_(1) = 100 g`
`Delta T_(b) = 1^(@) C or 1 K`
Substituting these value in the formula
`M_(B) = (1000 xx 2.53 K mol^(-1) xx 10 g)/( 100 xx 1K)`
`M_(B) = 253 g mol^(-1) `
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