Three liquids `A, B` and `C` having same specific heat and mass m , `2`m and `3` m have temperature `20^(@)C , 40^(@)C` and `60^(@)C` respectively. Temperature of the mixture when:
`{:(,"Column-I",,"Column-II"),((A),"A and B are mixed",(p),35^(@)C),((B),"A and C are mixed",(q),52^(@)),((C),"B and C are mixed",(r),50^(@)),((D),"A,B and C all three are mixed",(s),45^(@)),(,,(t),"None"):}`

Explanation

To find the equilibrium temperatures when different combinations of three liquids A, B, and C are mixed, we will use the principle of conservation of energy, which states that the heat lost by the hotter liquid will be equal to the heat gained by the colder liquid.

### Given Data:
- Liquid A: mass = m, temperature = 20°C
- Liquid B: mass = 2m, temperature = 40°C
- Liquid C: mass = 3m, temperature = 60°C

### Step-by-Step Solutions:
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