In the Bohr's model of hy drogen atom, the electron moves around the nucleus in a circular orbit of radius `5xx10^(-11) m`. Its time period is `1.5xx10^(-16)s`. The current associated with the electron motion is:-

Options

A. zero
B. `1.6xx10^(-19)A`
C. `0.17A`
D. `1.07xx10^(-3)A`

Explanation

To find the current associated with the motion of the electron in the Bohr model of the hydrogen atom, we can follow these steps:

### Step 1: Understand the concept of current
Current (I) is defined as the amount of charge (Q) passing through a point in a circuit per unit time (T). Mathematically, it is given by:
\[ I = \frac{Q}{T} \]

### Step 2: Identify the charge of the electron
In this case, the charge (Q) associated with the electron is the elementary charge, which is:
\[ Q = e = 1.6 \times 10^{-19} \, \text{C} \]

### Step 3: Identify the time period
The time period (T) given in the problem is:
\[ T = 1.5 \times 10^{-16} \, \text{s} \]

### Step 4: Substitute the values into the current formula
Now, we can substitute the values of charge and time period into the current formula:
\[ I = \frac{Q}{T} = \frac{1.6 \times 10^{-19}}{1.5 \times 10^{-16}} \]

### Step 5: Perform the calculation
Now, we will calculate the current:
\[ I = \frac{1.6 \times 10^{-19}}{1.5 \times 10^{-16}} = \frac{1.6}{1.5} \times 10^{-3} \]
\[ I \approx 1.0667 \times 10^{-3} \, \text{A} \]

### Step 6: Round off the answer
Rounding off to two significant figures, we get:
\[ I \approx 1.1 \times 10^{-3} \, \text{A} \]

### Final Answer
Thus, the current associated with the electron motion is approximately:
\[ I \approx 1.1 \times 10^{-3} \, \text{A} \]