Home
Class 10
MATHS
To divide a line segment AB in the ratio...

To divide a line segment AB in the ratio 4:7, a ray AX is drawn first such that `angleBAX` is an acute angle and then points `A_(1),A_(2),A_(3),…..` are located at equal distance on the ray AX and the point B is joined to

Answer

Step by step text solution for To divide a line segment AB in the ratio 4:7, a ray AX is drawn first such that angleBAX is an acute angle and then points A_(1),A_(2),A_(3),….. are located at equal distance on the ray AX and the point B is joined to by MATHS experts to help you in doubts & scoring excellent marks in Class 10 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • NEW TYPOLOGIES INTRODUCED BY CBSE FOR BOARD 2021-22 EXAM

    OSWAL PUBLICATION|Exercise UNIT-V TRIGONOMETRY (CHAPTER 10 - INTRODUCTION TO TRIGONOMETRY AND TRIGONOMETRIC IDENTITIES) |1 Videos

  • NEW TYPOLOGIES INTRODUCED BY CBSE FOR BOARD 2021-22 EXAM

    OSWAL PUBLICATION|Exercise UNIT-V TRIGONOMETRY (CHAPTER 10 - INTRODUCTION TO TRIGONOMETRY AND TRIGONOMETRIC IDENTITIES) (SELF ASSESSMENT)|5 Videos

  • NEW TYPOLOGIES INTRODUCED BY CBSE FOR BOARD 2021-22 EXAM

    OSWAL PUBLICATION|Exercise UNIT-IV GEOMETRY (CHAPTER 9 -CONSTRUCTIONS)|1 Videos

  • MAT STAGE I 2019-2020

    OSWAL PUBLICATION|Exercise QUESTION PART |100 Videos

  • NTSE 2019 -20

    OSWAL PUBLICATION|Exercise Probability Stage -2|1 Videos

Similar Questions

Explore conceptually related problems

Divide a line segment AB in the ratio 4:5, a ray AX is drawn first such that angle BAX is an acute angle and then points A_1, A_2, A_3 , ........ are located at equal distances on the ray AX which should be joined to B?

To divide a line segment BC internally in the ratio 3 : 5, we draw a ray BX such that angle CBX is an acute angle. What will be the minimum number of points to be located at equal distances, on ray BX?

Knowledge Check

  • To divide a line segment AB in the ratio 5:7, first a ray AX is drawn, so that /_BAX is an acute angle and then at equal distances point are marked on the ray AX such that the minimum number of these points is

    A
    8
    B
    10
    C
    11
    D
    12

  • To divide a line segment AB in the ratio 2:5 , first a ray AX is drawn, so that BAX is an acute angle and then at equal distance points are marked on the ray AX such that the minimum number of these point is:

    A
    2
    B
    5
    C
    4
    D
    7

  • To divide a line segment AB in the ratio 5:6, draw a ray AX such that angleBAX is an acute angle, the draw a ray BY parallel to AX and the points A_(1),A_(2),A_(3),….." and " B_(1),B_(2),B_(3),….. are located to equal distances on ray AX and BY, respectively. Then, the points joined are

    A
    `A_(5) " and " B_(6)`
    B
    `A_(6) " and " B_(5)`
    C
    `A_(4) " and " B_(5)`
    D
    `A_(5) " and " B_(4)`

    • Similar Questions

    Explore conceptually related problems

    Divide a line segment AB in the ratio 4:5, the points A_1, A_2, A_3,....and B_1, B_2, B_3 ,.... are located at equal distances on the ray AX and BY respectively. Which two points should be joined to divide a line segment?

    Divide a line segment AB in the ratio 3:7, What is the minimum number of points marked on a ray AX at equal distances?

    To constuct a triangle similar to a given DeltaABC with its sides (7)/(3) of the corresponding side of DeltaABC , draw a ray BX making acute angle with BC and X lies on the opposite side of A with respect of BC. The points B_(1),B_(2),…..,B_(7) are located at equal distances on BX, B_(3) is joined to C and then a line segment B_(6)C' is drawn parallel to B_(3)C , where C' lines on BC produced. Finally line segment A'C' is drawn parallel to AC.

    In the figure, if B_(1), B_(2), B_(3) , and A_(1), A_(2), A_(3), ….. have been marked at equal distances. In what ratio C divides AB?

    The point which divides the line segment joining the points (7, -6) and (3, 4) in ratio 1 : 2 internally lies in the

    Home
    Profile