To divide a line segment AB in the ratio 4:7, a ray AX is drawn first such that `angleBAX` is an acute angle and then points `A_(1),A_(2),A_(3),…..` are located at equal distance on the ray AX and the point B is joined to

To divide a line segment AB in the ratio 5:7, first a ray AX is drawn, so that /_BAX is an acute angle and then at equal distances point are marked on the ray AX such that the minimum number of these points is

To divide a line segment BC internally in the ratio 3 : 5, we draw a ray BX such that angle CBX is an acute angle. What will be the minimum number of points to be located at equal distances, on ray BX?

To divide a line segment AB in the ratio 5:6, draw a ray AX such that angleBAX is an acute angle, the draw a ray BY parallel to AX and the points A_(1),A_(2),A_(3),….." and " B_(1),B_(2),B_(3),….. are located to equal distances on ray AX and BY, respectively. Then, the points joined are

To constuct a triangle similar to a given DeltaABC with its sides (7)/(3) of the corresponding side of DeltaABC , draw a ray BX making acute angle with BC and X lies on the opposite side of A with respect of BC. The points B_(1),B_(2),…..,B_(7) are located at equal distances on BX, B_(3) is joined to C and then a line segment B_(6)C' is drawn parallel to B_(3)C , where C' lines on BC produced. Finally line segment A'C' is drawn parallel to AC.

In the figure, if B_(1), B_(2), B_(3) , and A_(1), A_(2), A_(3), ….. have been marked at equal distances. In what ratio C divides AB?

The point which divides the line segment joining the points (7, -6) and (3, 4) in ratio 1 : 2 internally lies in the