A block of mass m kg is pushed up against a wall by a force P that makes an angle `'theta'` with the horizontal as shown in figure. The coefficient of static friction between the block and the wall is `mu`. The minimum value of P that allows the block to remain stationary is

Explanation

To solve the problem of finding the minimum value of force \( P \) that allows the block to remain stationary against the wall, we can follow these steps:

### Step 1: Identify Forces Acting on the Block
The forces acting on the block are:
- The weight of the block, \( mg \) (acting downwards).
- The applied force \( P \) at an angle \( \theta \) with the horizontal, which can be resolved into two components:
- Horizontal component: \( P \cos \theta \) (acting towards the wall).
- Vertical component: \( P \sin \theta \) (acting upwards).
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