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A radionuclide with half - life 1620 s i...

A radionuclide with half - life 1620 s is produced in a reactor at a constant rate of 1000 nuclei per second. During each decay energy, 200 MeV is released. If the production of radionuclides started at t = 0, then the rate of release of energy at t = 3240 s is

A

`N=(PT)/(log_(e)2)[1-e^(-((log_(e)2)/(t))t)]`

B

`N=(PT)/(log_(e)2)[1-e^(-((log_(e)4)/(t))t)]`

C

`N=(PT)/(log_(e)4)[1-e^(-((log_(e)2)/(T))t)]`

D

`N=(PT)/(log_(e)2)[1+e^(-((log_(e)2)/(T))t)]`

Text Solution

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The correct Answer is:
A
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