Home
Class 12
CHEMISTRY
How many g atoms and number of atoms are...

How many `g` atoms and number of atoms are there in (a) `60 g` carbon, (b) `22.4 g Cu`, and (c ) `72.52 g` lead. Given atomic masses of `C, Cu` and `Pb` are 12,63.6, and 207.2, respectively. (Avogadro's number `= 6.02 xx 10^(23))`.

A

`CH_3 COOH`

B

`HCHO`

C

`CH_3 OOCH_3`

D

`CH_3 CHO`

Text Solution

Verified by Experts

The correct Answer is:
B
Organic compount containing C, H O ) `overset("dissociation")to underset(7.5 "gram")H + underset("60 gram")O + underset("48.5 gram")C`
% of H in organic compount = `7.5/116 xx 100 = 6.465 %`
(A) % of H = `4/60 xx 100 = 6.6 `
(B) % of H = `2/30 xx 100 = 6.6`
(C) % of H `= 6/62 xx 100 = 7.677`
(D) % of `H = 4/44 xx 100 = 9.09`
Promotional Banner

Topper's Solved these Questions

  • JEE MAINS 2022

    JEE MAINS PREVIOUS YEAR|Exercise CHEMISTRY (SECTION-A)|20 Videos

  • JEE MAINS 2021

    JEE MAINS PREVIOUS YEAR|Exercise Chemistry (Section B )|10 Videos

  • JEE MAINS 2023 JAN ACTUAL PAPER

    JEE MAINS PREVIOUS YEAR|Exercise Question|360 Videos

Similar Questions

Explore conceptually related problems

How many g atoms and number of atoms are there n (a) 60 g carbon, (b) 22.4 g Cu , an (c ) 72.52 g lead. Given atomic masses of C, Cu and Pb are 12,63.6, and 207.2, respectively. (Avogadro's number = 6.02 xx 10^(23)) .

The number of atoms present in a 0.635 g of Cu piece will be :

It the atomic masses of C and S are 12 and 32 respectively, then atom of S is how many times heavier than an atom of carbon ?

Convert into moles : (a) 12 g of oxygen gas (b) 20 g of water (c ) 22 g of carbon dioxide (Atomic masses : O = 16 u, H = 1 u and C = 12 u )

How many hydrogen atoms are contained in 1.50 g of glucose (C_6 H_(12) O_6) ?

Knowledge Check

  • Number of atoms present in 1.6 g of methane is

    A
    `6.02xx10^(23)`
    B
    `3.01xx10^(23)`
    C
    `3.01xx10^(22)`
    D
    `6.02xx10^(22)`

  • The number of atoms present in a 0.635 g of Cu piece will be :

    A
    `6.023 xx 10^(-23)`
    B
    `6.023 xx 10^(23)`
    C
    `6.023 xx 10^(22)`
    D
    `6.023 xx 10^(21)`

  • A + 2B+ 3C AB_2 C_3 Reaction of 6.0 g of A, 6.0 xx 10^(23) atoms of B, and 0.036 mol of C yields 4.8 g of compound AB_(2)C_(3) . If the atomic mass of A and C are 60 and 80 amu, respectively. The atomic mass of B is: (Avogadro number = 6 xx 10^(23) )

    A
    70 amu
    B
    60 amu
    C
    50 amu
    D
    40 amu