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Find the value of x satisfying the equat...

Find the value of x satisfying the equations `log_(3)(log_(2)x)+log_(1//3)(log_(1//2)y)=1` and `xy^(2)=9`

Text Solution

Verified by Experts

The correct Answer is:
x=729

`log_(3)(log_(2)x)+log_(1//3)(log_(1//2)y)=1`
`rArr log_(3)(log_(2)x)-log_(3)(-log_(2)y)=1`
`rArr log_(3)(-(log_(2)x)/(log_(2)y))=1`
`rArr -(log_(2)x)/(log_(2)y)=3`
`rArr xy^(3)=1`
Also, `xy^(2)=9`
`rArr =(1)/(9)`
`therefore x=729`
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Knowledge Check

  • Consider the system of equations log_(3)(log_(2)x)+log_(1//3)(log_(1//2)y) =1 and xy^(2) = 9 . The value of 1/y lies in the interval

    A
    `(5, 7)`
    B
    `(7, 10)`
    C
    `(11, 15)`
    D
    `(25, 30)`
  • Consider the system of equations log_(3)(log_(2)x)+log_(1//3)(log_(1//2)y) =1 and xy^(2) = 9 . The value of x in the interval

    A
    `(200, 300)`
    B
    ` (400, 500)`
    C
    `(700, 800)`
    D
    none of these
  • Find the values of x and y for the given equation xy^2=4 and log_3(log_2x)+log_(1//3)(log_(1//2)y)=1 :

    A
    `x=1/8,y=64`
    B
    `x=1/4,y=48`
    C
    `x=64,y=1/4`
    D
    none of these
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