Home
Class 12
PHYSICS
A particle moves on a circular path of r...

A particle moves on a circular path of radius R under the action of two constant forces `F_(1)and F_(2). F_(1)` act along positive x axis and `F_(2)` acts along positive y-axis. Find the work done by `F_(1)and F_(2)` in moving the particle from position A to position B as shown in figure.

Text Solution

Verified by Experts

Displacement of the particle from A to B is `vecs`
As force `F_(1)` is constant thus work done by `vecF_(1)` is constants thus work done by `vecF_(1)=F_(1)xx`(component of displacement in direc tion of `vecF_(1)`
Now, component of displacement in direction of `F_(1)` is equal to R.
Therefore work done by,
`F_(1)=F_(1)` R joules
Similarly work done by `F_(2)=F_(2)xx R` joules
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • WORK, ENERGY AND POWER

    AAKASH INSTITUTE|Exercise TRY YOURSELF|95 Videos
  • WORK, ENERGY AND POWER

    AAKASH INSTITUTE|Exercise SECTION-A (OBJECTIVE TYPE QUESTIONS (ONE OPTIONISCORRECT)|60 Videos
  • WORK, ENERGY AND POWER

    AAKASH INSTITUTE|Exercise Assignment (SECTION - D)|15 Videos
  • WAVES

    AAKASH INSTITUTE|Exercise ASSIGNMENT ( SECTION-D ( Assertion - Reason Type Questions ))|12 Videos

Similar Questions

Explore conceptually related problems

If vec(F)=yhati+xhatj then find out the work done in moving the particle from position (2, 3) to (5, 6)

If vec(F) = y hat(i) + x hat(j) then find out the work done in moving the particle from position (2,3) to (5,6)

Knowledge Check

  • A particle of mass M moves with constant speed along a circular path of radius r under the action of a force F. Its speed is

    A
    `sqrt((r F)/(m))`
    B
    `sqrt((F)/(r))`
    C
    `sqrt(F m r)`
    D
    `sqrt((F)/(m r))`
  • A particle of mass 'm' moves with a constant speed along a circular path of radius r under the action of a force F .Its speed is given by

    A
    `sqrt((Fr)/(m))`
    B
    `sqrt((F )/(mr ))`
    C
    `sqrt((F )/(r ))`
    D
    `sqrt(Fmr)`
  • A particle is moving in a circular path of radius r under the action of a force F. If at an instant velocity of particle is v, and speed of particle is increasing, then

    A
    `vecF.vecv=0`
    B
    `vecF.vecc gt 0`
    C
    `vecF.vecv lt0`
    D
    `vecF.vecvge0`
  • Similar Questions

    Explore conceptually related problems

    A force F acting on a particle varies with the position x as shown in figure. Find the work done by this force in displacing the particle from

    A vector F_(1) acts along positive x -axis. If its vector product with another F_(2) is zero, then F_(2) could be

    Two forces F_(1)=1N and F_(2)=2N act along the lines x=0 and y=0, respectively. Then find the resultant of forces.

    Two forces f_(1)=4N and f_(2)=3N are acting on a particle along positve X- axis and negative y- axis respectively. The resultant force on the particle will be -

    A force F acting on a particle varies with the position x as shown in the graph. Find the work done by the force in displacing the particle from x =-a to x = +2a . .