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If the magnitudes of two vectors are 3 and 4 and magnitude of their scalar product is 6 what is the angle between the vectors ?

Text Solution

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`A=3,B=4A=B6`
`cos theta(barA.barB)/(AB)`
`cos theta=(vecA.vecB)/(AB)=(6)/(3xx4)=1/2`
`theta=60^(@)`
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