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A heavy metallic rod of non-uniform mass...

A heavy metallic rod of non-uniform mass distribution, is hanged vertically from a rigid support. The linear mass density varies as `lambda_((x))=k xx x` where x is the distance measured along the length of rod, from its lower end. Find extension in rod due to its own weight.

Text Solution

Verified by Experts

The correct Answer is:
`Deltal=(kgl^(3))/(6AY)`
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Knowledge Check

  • Find centre of mass of given rod of linear mass density lambda=(a+b(x/l)^2) , x is distance from one of its end. Length of the rod is l .

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