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The acceleration of a particle which sta...

The acceleration of a particle which starts from rest varies with time according to relation a=2t+3. The velocity of the particle at time t would be

A

`2t^3+3`

B

`t^2+3t`

C

`2t^2+3t`

D

zero

Text Solution

AI Generated Solution

The correct Answer is:
To find the velocity of a particle whose acceleration varies with time according to the relation \( a = 2t + 3 \), we can follow these steps: ### Step 1: Understand the relationship between acceleration and velocity Acceleration \( a \) is defined as the rate of change of velocity \( v \) with respect to time \( t \): \[ a = \frac{dv}{dt} \] Given that \( a = 2t + 3 \), we can write: \[ \frac{dv}{dt} = 2t + 3 \] ### Step 2: Rearrange the equation for integration We can rearrange the equation to facilitate integration: \[ dv = (2t + 3) dt \] ### Step 3: Integrate both sides Now, we will integrate both sides. The left side will be integrated with respect to \( v \) and the right side with respect to \( t \): \[ \int dv = \int (2t + 3) dt \] ### Step 4: Perform the integration The left side integrates to: \[ v \] The right side integrates as follows: \[ \int (2t + 3) dt = \int 2t \, dt + \int 3 \, dt = t^2 + 3t + C \] where \( C \) is the constant of integration. ### Step 5: Apply initial conditions Since the particle starts from rest, at \( t = 0 \), the initial velocity \( v = 0 \): \[ 0 = 0^2 + 3(0) + C \implies C = 0 \] ### Step 6: Write the final expression for velocity Thus, the expression for velocity \( v \) at any time \( t \) is: \[ v = t^2 + 3t \] ### Final Answer: The velocity of the particle at time \( t \) is: \[ v(t) = t^2 + 3t \] ---
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Knowledge Check

  • The acceleration of a'particle starting from rest, varies with time according to the relation a=kt+c . The velocity of the particle after time t will be :

    A
    `kt^(2)+ct`
    B
    `1.2 kt^(2)+ct`
    C
    `1/2 (kt^(2)+ct)`
    D
    `kt^(2)+1/2 ct`
  • The acceleration of a particle starting from rest, varies with time according to the relation A=-aomegasinmegat. . The displacement of this particle at a time t will be

    A
    `-(1)/(2)(aomega^(2)sinomegat)t^(2)`
    B
    `aomegasinomegat`
    C
    `aomegacosomegat`
    D
    `a(sinomegat)/omega -at`
  • The acceleration a of a body, starting from rest varies with time t following the cquation a= 3t + 4. The velocity of the body at timet =2 s will be

    A
    `10 m s^(-1)`
    B
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    C
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    D
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