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An object projected with same speed at t...

An object projected with same speed at two different angles covers the same horizontal range R. If the two times of flight be ` t_(1) and t_(2)` . The range is ` 1/alpha "gt"_(1) t_(2), ` the value of `alpha` is

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Knowledge Check

  • Two particles are projected from the same point with the same speed at different angles theta_(1) and theta_(2) to the horizontal. If their respective times of flights are T_(1) and T_(2) and horizontal ranges are same then a) theta_(1)+theta_(2)=90^(@) , b) T_(1) =T_(2)tan theta_(1) c. T_(1) =T_(2)tan theta_(2) , d) T_(1)sin theta_(2)=T_(2)sin theta_(1)

    A
    `a,b,d`are correct
    B
    `a,c,d`are correct
    C
    `b,c,d`are correct
    D
    `a,b,c`are correct

  • A projectile has same range for two angules of projection. If times of flight in two cases are t_(1) and t_(2) then the range of the projectilie is

    A
    `1/2 g t_(1)t_(2)`
    B
    `1/4g t_(1)t_(2)`
    C
    `g t_(1) t_(2)`
    D
    `1/8 g t_(1)t_(2)`

  • Two particles are projected from the same point with the same speed at different angles theta_1 & theta_2 to the horizontal. They have the same range. Their times of flight are t_1 & t_2 respectily

    A
    `(t_1)/(t_2)=tan^2theta_1`
    B
    `(t_1)/(sintheta_1)=(t_2)/(costheta_2)`
    C
    `(t_1)/(t_2)=tantheta_1`
    D
    `(t_1)/(t_2)=tan^2theta_2`