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Calculate DeltafH^(@) ("in" (kJ)/("mol")...

Calculate `Delta_fH^(@) ("in" (kJ)/("mol"))` for `C_2H_6(g)`, if `Delta_cH^@` `[C("graphite")] = –393.5 (kJ)/(mol)`, `Delta_c H^@ [(h_2)g]= –286 (kJ)/(mol)` and `Delta_cH^@ [C_6H_6(g)]` = `–1560 (kJ)/(mol)`

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Calculate the resonance enegry of toulene (use Kekule structure form the following data C_(7)H_(8)(l) +9O_(2)(g) rarr 7CO_(2)(g) +4H_(2)O(l)+ DeltaH, DeltaH^(Theta) =- 3910 kJ mol^(-1) C_(7)H_(8)(l) rarr C_(7)H_(8)(g), DeltaH^(Theta) = 38.1 kJ mol^(-1) Delta_(f)H^(Theta) (water) =- 285.8 kJ mol^(-1) Delta_(f)H^(Theta) [CO_(2)(g)] =- 393.5 kJ mol^(-1) Heat of atomisaiton of H_(2)(g) = 436.0 kJ mol^(-1) Heat of sulimation of C(g) = 715.0 kJ mol^(-1) Bond energies of C-H, C-C , and C=C are 413.0, 345.6 , and 610.0 kJ mol^(-1) .

Calculate Delta_(r) H^(@) for Fe_(2) O_(3) (s) + 3 CO(g) to 2 Fe (s) + 3 CO_(2) (g) Given : Delta_(f) H^(@) (Fe_(2) O_(3) , s) = -822.2 kJ/mol Delta_(f) H^(@) (CO , g) = -110.5 kJ//mol , Delta_(f) H^(@) (CO_(2) , g) = -393.5 kJ/mol

Knowledge Check

  • What is the standard enthalpy change at 298 K for the following reaction? CO_(2) (g)+ C("diamond") rarr 2CO(g) Given : DeltaH_(f)^(@)(CO,g) = - 110.5 kJ//mol : Delta H_(f)^(@)(CO_(2),g) = - -393.5 kJ//mol Delta H_("transition")^(@)[C("graphite")rarr C("diamond")] = 2.0 kJ//mol

    A
    `-172.5 kJ//mol`
    B
    `-170.5 kJ//mol`
    C
    `+172.5 kJ//mol`
    D
    `170.5 kJ//mol`
  • Delta_(f)U^(c-) of formation of CH_(4)(g) at certain temperature is -393kJ mol^(-1) . Thevalue of Delta_(f)H^(c-) is

    A
    zero
    B
    ` lt Delta_(f)U^(c-)`
    C
    `gt Delta_(f)U^(c-)`
    D
    equalto `Delta_(f)U^(c-)`
  • On the basis of thermochemical equations (i),(ii) and (iii), which of the algebric relationship is correct. C("graphite") + O_(2)(g) to CO_(2)(g), Delta_(r)H = x kJ "mol"^(-1) C("graphite") + 1/2 O_(2)(g) to CO(g), Delta_(r)H = y KJ "mol"^(-1) CO(g) + 1/2O_(2)(g) to CO_(2)(g), Delta_(r)H = z kJ "mol"^(-1)

    A
    z = x + y
    B
    x = y - z
    C
    x = y + z
    D
    y = 2z - x
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