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What is the atomic weight of an element ...

What is the atomic weight of an element X for which a sample containing `1.58xx10^(22)` atoms weigh 1.05 g?

A

28 g

B

20 g

C

40 g

D

23 g

Text Solution

Verified by Experts

The correct Answer is:
C
We know that one mole of an lement=`6.02xx10^(23)` atoms
=atomic weight of the element
Now, `1.58xx10^(22)` atoms weigh 1.05g
`therefore6.02xx10^(23)` atoms weigh
`=((1.05xx6.02xx10^(23)))/(1.58xx10^(22))=40g`
Atomic weight of X=40g
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-PRACTICE SET 03-PAPER 1 (PYSICS & CHEMISTRY)
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