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What is the atomic weight of an element ...

What is the atomic weight of an element X for which a sample containing `1.58xx10^(22)` atoms weigh 1.05 g?

A

28 g

B

20 g

C

40 g

D

23 g

Text Solution

Verified by Experts

The correct Answer is:
C
We know that one mole of an lement=`6.02xx10^(23)` atoms
=atomic weight of the element
Now, `1.58xx10^(22)` atoms weigh 1.05g
`therefore6.02xx10^(23)` atoms weigh
`=((1.05xx6.02xx10^(23)))/(1.58xx10^(22))=40g`
Atomic weight of X=40g
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Knowledge Check

  • Which of the following samples contain 2.0 xx 10^(23) atoms?

    A
    `8.0 g O_(2)`
    B
    `3.0 g Be`
    C
    `4.0 g C`
    D
    `1.0 g He`

  • Equals number of atoms are contained in one gram atomic weight of each element and the same number of molecules are found in one gram molecules weight of any compound . The terms gram atomic weight and gram molecular weight are used to refer to a fixed numer(Avogadro's number 6.022xx10^(23)) of particle. the term 'mole' stands for the amount of material which contains these number of particles. What will be the gram atomic weight of Mg if 24 g of ._(24)Mg^(24) contains 6.022 xx 10^(23) atoms?

    A
    12 gm
    B
    36 g
    C
    24 g
    D
    48 g

  • If the atomic weight of an element is 23 times that of the lightest element and it has 11 protons, then it contains.

    A
    `11` protons, `23` neutrons, `11` electrons
    B
    `11` protons, `11` neutrons, `11` electrons
    C
    `11` protons, `12 "neutrons"`, `11` electrons
    D
    `11` protons, `11` neutrons, `23` electrons.
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