The largest number of molecules is in:

Options

A. 34 g of `H_(2)O`
B. 28 g of `CO_(2)`
C. 46 g of `CH_(3)OH`
D. 54g of `N_(2)O_(5)`

Answer

A

Explanation

(a) 34 g of `H_(2)O`
`because` 18 g `H_(2)O=6xx10^(23)` molecule
`therefore34g` of `H_(2)O=(6xx10^(23)xx34)/(18)`
`=11.33xx10^(23)` molecules
(b) 28 of `CO_(2)`
`because` 44 g of `CO_(2)=6xx10^(23)` molecules
`therefore` 28 g of `CO_(2)=(6xx10^(23)xx28)/(44)`
`=3.8xx10^(23)` molecules
(c) 46 g of `CH_(3)OH`
`because` 32g of `CH_(3)OH=6xx10^(23)`
molcules
`therefore46g` of `CH_(3)OH=(6xx10^(23)xx46)/(32)`
`=8.625xx10^(23)` molecules
(d) 54 d of `N_(2)O_(5)`
`because 108g` of
`N_(2)O_(5)=6xx10^(23)` molecules
thus, 34 g `H_(2)O` contains the largest number of molecules.