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When SO(2) is passed through an acidifie...

When `SO_(2)` is passed through an acidified `K_(2)Kr_(2)O_(7)` solution, the oxidation state of sulphur changes from

A

`+4` to 0

B

`+4` to `+2`

C

`+4` to `+6`

D

`+6` to `4`

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • When SO_(2) is passed through acidified K_(2)Cr_(2)O_(7) solution

    A
    the solution turns blue
    B
    the solution is decolourised
    C
    `SO_2` is reduced
    D
    green `Cr_2(SO_4)_3` is formed.

  • When SO_(2) is passed through acidified K_(2)Cr_(2)O_(7) solution

    A
    The solution turns blue
    B
    The solution is decolourised
    C
    `SO_(2)` is reduced
    D
    Green `Cr_(2)(SO_(4))_(3)`is formed

  • When SO_(2) is passed through acidified K_(2)Cr_(2)O_(7) solution

    A
    the solution turns blue
    B
    the solution is decolourized
    C
    reduction of `SO_(2)` takes place
    D
    green `Cr_(2)(SO_(4))_(3)` is formed

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    When sulphur dioxide is passed in an acidified K_(2)Cr_(2)O_(7) solution, the oxidation state of sulphur is changed from:

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    When SO_(2) is passed in acidified K_(2)Cr_(2)O_(7) solution oxidation state of S changed from

    When SO_2 is passed through acidified K_2Cr_2O_7 solution

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