A Kundt's tube apparatus has a steel rod of length 1.0 m 66. clamped at the centre. It is vibrated in its fundamental mode at a frequency of 2600 Hz. The lycopodium powder dispersed in the tube collects into heaps separated by 6.5 cm. Calculate the speed of sound in steel and in air.

Answer

A, B, C

Explanation

a. Here given `L=10/2=0.5m`
`d_3=6.5cm=6.5xx10^-2m`
As Kudnit's the Appartus is closed organ pipe its fundamental frequency
`rarr n=10/2
`rarr `V_r=2600x4xx0.5`
`r=5200m/s`
b. `V_r/V_a=(2L_r)/d_a`
`rarr V_a=(52xx6.5xx10^-2)/(2xx0.5)`
=338m/s`