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A spherical Gaussian surface encloses, a...

A spherical Gaussian surface encloses, and is concentric with, a charged spherical conductor. If the TNEI over the Gaussian surface is negative, what can you say about the electric field `vecE` at a point on the surface?

Text Solution

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`vecE` is radially inward.
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Knowledge Check

  • The Gaussian surface needed for calculating the electric field due to a charge distribution is

    A
    any surface around the charge distribution
    B
    only spherical surface.
    C
    any closed surface around the charge.
    D
    only cylindrical surface.

  • If q is the charge per unit area on the surface of a conductor, then the electric field intensity at a point on the surface is

    A
    `((q)/(epsilon_(0)))` normal to surface
    B
    `((q)/(2epsilon_(0)))` normal to surface
    C
    `((q)/(epsilon_(0)))` tangential to surface
    D
    `((q)/(2epsilon_(0)))` tangential to surface

  • Electric field intensity at a point a hollow charged spherical conductor

    A
    is zero
    B
    is constant
    C
    increase with the distance from the centre of the sphere
    D
    none of these

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