The peressure exerected by a certain mass of enclosed gas at 300 K is ` 5 xx 10^(4) N//m^(2)` .what will be the pressure exerted by the has ay 600 K if the volume of the gas is kept constant ?

Explanation

Here ` p prop T " " therefore P_(2)/P_(1) = T_(2)/T_(1) = 600/300 = 2 `
`p_(2) = 2p_(1) = 2 xx 5 xx 10^(4) = 10^(5) N//m^(2)`
Gives the required pressure.