Suppose you are on a trail and you have a map with two points marked on it: the start and end of the trail. Somewhere between these points, locate a resting spot that splits the trail in a ratio of m:n. How would you determine its location on the map? The answer is the section formula. In coordinate geometry, the section formula is an interesting tool that helps find a point that lies between any two locations, either internally or externally.
The Section Formula is a mathematical tool to locate a point that divides a line segment connecting two given points in a certain ratio. It offers a means of calculating the position of the dividing point from the known positions of the endpoints and the specified ratio in which the segment is divided. The formula finds extensive application in coordinate geometry in solving problems that involve dividing line segments internally as well as externally.
Based on how a point divides a line segment, the section formula can be divided into two types. These two types include:
Internal division in a line segment specifically means when a point divides it between the two endpoints. In other words, a point lies on the segment; dividing it into two parts in a given ratio is known as internal division. Understand it like this: for a line segment joining the points A(x1,y1) and B(x2,y2), if point P divides the segment AB in the ratio m:n, then the coordinates of point P(x,y) can be calculated with the section formula for internal division. Which is expressed as:
Internal division is an important part of section formula class 10, while studying coordinate geometry, which forms a base for studying these concepts in higher standards.
External division refers to the division of a line segment by a point outside the segment. This simply means the point doesn’t actually divide the segment itself; it extends beyond the endpoints. For calculating the coordinates of this point, consider a point P(x,y) that divides the line segment joining two points A(x1,y1) and B(x2,y2) externally in the ratio m:n, then the coordinates of point P are given by the section formula of external division:
The section formula for a point dividing a line segment can be derived using the similarity rules for a pair of triangles. In the figure given below, two right-angled triangles, ACP and PDB, are given. The hypotenuse of these triangles is the ratio of lines AB, which is m:n. Here, the sides AC and PD of the triangles are parallel to each other.
In
∠PAC = ∠BPD (Corresponding angles)
∠ACP = ∠PDB (Right angle)
Since,
Hence,
According to the figure,
AC = x – x1 …(2)
PD = x2 – x …(3)
From equations 1, 2, and 3:
Now, for y coordinates
CP = y – y1 ….(4)
BD = y2 – y …..(5)
From equations 1, 4, and 5
According to equations a and b, the coordinates P(x,y), we have:
Similar to the derivation of internal division, the formula for external division can also be derived, which gives the result:
The section formula, either internal or external, is used in a large number of topics of mathematics; these are:
Problem 1: Find the coordinates of the point P that divides the segment joining A(2,3) and B(4,6) in the ratio 4:3, internally.
Solution: Given that, A(2,3) and B(4,6) and m:n = 4:3
The section formula for internal division is
Problem 2: Find the coordinates of the point P that divides the line segment joining A(1,2) and B(4,5) externally in the ratio 2:3, externally.
Solution: Given that, A(1,2) and B(4,5) and m:n = 2:3
Using the section formula for external division:
Problem 3: The point P(x,y) divides the line segment joining A(2,3) and B(8,7) in a certain ratio. If the coordinates of point P are (5,5), find the ratio.
Solution: Given that A(2,3), B(8,7), and P(5,5)
Let the ratio of the line divided by a point P = k:1
Now, using the section formula:
Hence, the required ratio is 1:1, which also means that P is a midpoint to AB.
(Session 2025 - 26)