A student measures the time period of `100` ocillations of a simple pendulum four times. The data set is `90 s, 91 s, 95 s, and 92 s`. If the minimum division in the measuring clock is `1 s`, then the reported men time should be:

Options

A. (a) `92 +- 1.8 s`
B. (b) `92 +- 3 s`
C. ( c ) `92 +- 2 s`
D. ( d ) `92 +- 5.0 s`

Answer

A

Explanation

(a) `DeltaT = (| DeltaT_(1)| + |DeltaT_(2)| + DeltaT_(3)| + |DltaT_(4))|/(4)`
`= (2+1+3+0)/(4) = 1.5`
As the resolution of measuring clock is `1.5` therefore the mean time should be `92+-1.5`