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Calculate the percent free SO(3) in an o...

Calculate the percent free `SO_(3)` in an oleum which is labelled `'118% H_(2) SO_(4)'`.

Text Solution

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(118 - 100), `= 18 g H_(2) O` combine with all the free `SO_(3)` in `100 g` of the oleum to give a total of `118 g _(2) SO_(4)`.
`18 g H_(2) O` combines with `80 g SO_(3)`.
Thus percent free `SO_(3)` in the oleum `= (18 xx 80)/(18) = 80%`
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