Home
Class 11
PHYSICS
Velocity of a particle at time t=0 is 2 ...

Velocity of a particle at time `t=0 is 2 m//s.` A constant acceleration of `2 m/s^2` acts on the particle for `2 s` at an angle of `60^@` with its initial velocity. Find the magnitude of velocity and displacement of particle at the end of `t=2s.`

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
`u=2 hati`

`a=(2 cos 60^@) hati+(2 sin 60^@) hatj`
`=(hati +sqrt3 hatj)`
`t=2s`
(i) `v=u+at=(2 hati)+(hati+sqrt3 hatj)(2)`
`=4 hati+2 sqrt3 hatj`
`:. |v|=sqrt((4)^2+(2sqrt3)^2)`
`=2sqrt7 m//s`
(ii) `s=ut+1/2 at^2=(2 hati)(2)+1/2(hati+sqrt3 hatj)(2)^2`
`=(6hati+2sqrt3 hatj)`
`:. |s|=sqrt((6)^2+(2sqrt3)^2)`
`=4sqrt3 m`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINEMATICS

    DC PANDEY|Exercise Exercise 6.8|5 Videos

  • KINEMATICS

    DC PANDEY|Exercise Exercise 6.9|6 Videos

  • KINEMATICS

    DC PANDEY|Exercise Exercise 6.6|5 Videos

  • GRAVITATION

    DC PANDEY|Exercise (C) Chapter Exercises|45 Videos

  • KINEMATICS 1

    DC PANDEY|Exercise INTEGER_TYPE|15 Videos

Similar Questions

Explore conceptually related problems

A particle of mass 1 kg has a velocity of 2m//s . A constant force of 2N acts on the particle for 1s in a direction perpendicular to its initial velocity. Find the velocity and displacement of the particle at the end of 1 s.

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

Knowledge Check

  • Velocity of a particle at time t=0 is 2ms^(-1) . A constant acceleration of 2ms^(-2) acts on the particle for 1 second at an angle of 60^(@) with its initial velocity. Find the magnitude of velocity at the end of 1 second .

    A
    `sqrt3 m//s`
    B
    `2sqrt3 m//s`
    C
    `4 m//s`
    D
    `8 m//s`

  • . If the velocity of a particle is (10 + 2 t 2) m/s , then the average acceleration of the particle between 2s and 5s is

    A
    `2m//s^(2)`
    B
    `4m//s^(2)`
    C
    `12m//s^(2)`
    D
    `14m//s^(2)`

  • Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

    A
    `18 ms^(-2)`
    B
    `12 ms^(-2)`
    C
    `15 ms^(-2)`
    D
    zero

    • Similar Questions

    Explore conceptually related problems

    Velocity of a particle at any time t is v=(2 hati+2t hatj) m//s. Find acceleration and displacement of particle at t=1s. Can we apply v=u+at or not?

    A particle starts from rest and moves with an acceleration of a={2+|t-2|}m//s^(2) The velocity of the particle at t=4 sec is

    The acceleration of a particle varies with time t as a=t^(2)+t+2 where t is in seconds. The particle starts with an initial velocity v-3m/s at t=0. find the velocity of the particle at the end of 5s.

    If the velocity of a particle is (10+2t^(2)m/s ,then the average acceleration of the particle between 2s and 5s is (in m/s^2)

    Velocity and acceleration of a particle at time t = 0 are u=(2hat(i)+3hat(j))m//s and a=(4hat(i)+2hat(j))m//s^(2) respectively. Find the velocity and displacement of particle at t = 2 s.

    Home
    Profile