Velocity of a particle at time `t=0 is 2 m//s.` A constant acceleration of `2 m/s^2` acts on the particle for `2 s` at an angle of `60^@` with its initial velocity. Find the magnitude of velocity and displacement of particle at the end of `t=2s.`
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Knowledge Check
Velocity of a particle at time t=0 is 2ms^(-1) . A constant acceleration of 2ms^(-2) acts on the particle for 1 second at an angle of 60^(@) with its initial velocity. Find the magnitude of velocity at the end of 1 second .
A
`sqrt3 m//s`
B
`2sqrt3 m//s`
C
`4 m//s`
D
`8 m//s`
. If the velocity of a particle is (10 + 2 t 2) m/s , then the average acceleration of the particle between 2s and 5s is
A
`2m//s^(2)`
B
`4m//s^(2)`
C
`12m//s^(2)`
D
`14m//s^(2)`
Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :
