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Velocity (in m/s) of a particle moving a...

Velocity (in m/s) of a particle moving along x-axis varies with time as, `v= (10+ 5t -t^2)` At time `t=0, x=0.` Find
(a) acceleration of particle at `t = 2 s` and
(b) x-coordinate of particle at `t=3s`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
(a) `a=(dv)/(dt)=5-2t`
At `t=2s`
`a=1 ms^2`
(b) `x=int_0^3 v dt =int_0^3(10+5t-t^2)dt`
`=[10t+2.5t^2-t^3/3]_0^3`
`=(10xx3)+(2.5)(3)^2-(3)^3/3`
`=43.5 m`
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