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Two particles are projected from a tower...

Two particles are projected from a tower horizontally in opposite directions with velocities `10 m//s and 20 m//s`. Find the time when their velocity vectors are mutually perpendicular. Take `g=10m//s^2`.

Text Solution

Verified by Experts

The correct Answer is:
B
`v_1 * v_2` = 0
`rArr (u_1 + a_1t)*(u_2 + a_2t) = 0`
` rArr (10hati - 10t hatj)* (-20hati-10thatj) = 0`
`rArr -200+100t^2 =0`
`rArr t = sqrt(2)` sec.
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Knowledge Check

  • From a tower of height 40 m , two bodies are simultaneously projected horizontally in opposite direction, with velocities 2 m s^-1 and 8 ms^-1 . respectively. The time taken for the velocity vectors of two bodies to become perpendicular to each other is :

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