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A particle is projected from ground with...

A particle is projected from ground with velocity `40(sqrt2) m//s at 45^@`. Find
(a) velocity and
(b) displacement of the particle after 2 s. `(g = 10 m//s^2)`

Text Solution

Verified by Experts

The correct Answer is:
A, B
`u = 40hati + 40hatj`
`a = -10hatj`
t = 2s

(a) Apply `v = u+ at` as a=constant
(b) Apply `s = ut + 1/2 at^2`
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