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Find time of flight and range of the pro...

Find time of flight and range of the projectile along the inclined plane as shown in figure. `(g = 10 m//s^2)`

Text Solution

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The correct Answer is:
A, C

`T = (2usin(alpha -beta))/(g cos beta)`
`((2)(20sqrt2)sin(45^@ -30^@))/((10)(cos 30^@)) = 1.69s`
`R = u^2/(gcos^2beta) [sin(2alpha-beta)-sinbeta]`
`=(20sqrt(2))^2/((10)cos^2 30^@) [sin(2xx45^@-30^@)- sin 30^@]`
`=39m`.
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In the figure shown, find. (a) time of flight of the projectile along the inclined plane. (b) range OP.

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Knowledge Check

  • The time of flight of a projectile on an upwardd inctined plane depends upon

    A
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    B
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    C
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  • A partile is projected up an incline (inclination angle = 30^(@) ) with 15sqrt(3) m//s at an angle of 30^(@) with the incline (as shown in figure) (g = 10 m//s^(2))

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    `1.5` sec later, angle between acceleration & velocity is `120^(@)`
    B
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    C
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    D
    Time of flight on the incline is `3` sec.
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