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A thin circular right of mass M and radi...

A thin circular right of mass `M` and radius `R` is rotating about its axis with an angular speed `omega_(0)` two particles each of mass `m` are now attached at diametrically opposite points. Find new angular speed of the ring.

Text Solution

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`I_(1)omega_(1)=I_(2)omega_(2)`
`thereforeomega_(2)=(I_(1))/(I_(2))omega_(1)`
`=((MR^(2))/(MR^(2)+2mR^(2)))omega_(0)`
`=((M)/(M+2m))omega_(0)`
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