Home
Class 11
PHYSICS
In the figure shown omega=(v)/(2R) in te...


In the figure shown `omega=(v)/(2R)` in terms of `hati` and `hatj` find linear velocities of particles M, N, R and S.

Text Solution

Verified by Experts


`omegaR=(v)/(2)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ROTATIONAL MECHANICS

    DC PANDEY|Exercise Exercise 12.8|3 Videos

  • ROTATIONAL MECHANICS

    DC PANDEY|Exercise Exercise 12.9|2 Videos

  • ROTATIONAL MECHANICS

    DC PANDEY|Exercise Exercise 12.6|4 Videos

  • ROTATION

    DC PANDEY|Exercise (C) Chapter Exercises|39 Videos

  • ROTATIONAL MOTION

    DC PANDEY|Exercise Integer Type Questions|17 Videos

Similar Questions

Explore conceptually related problems

In the figure shown upsilon=2m//s omega=5rad//s and CP=1m In terms of hati and hatj find linear velocity of particle P.

In the shown figure, a=2m//s^(2),omega=(2t)rods^(-1) and CP=1m In terms of hati and hatj , find linear acceleration of the particle at P at P at t=1 s

Knowledge Check

  • A disc of radius R rolls on a horizontal ground with linear acceleration a and angular acceleration alpha as shown in Fig. The magnitude of acceleration of point P as shown in the figure at an instant when its linear velocity is v and angular velocity is omega will be a

    A
    `sqrt((a+ralpha)^(2)+(romega^(2))^(2))`
    B
    `(ar)/R`
    C
    `sqrt(r^(2)alpha^(2)+r^(2)omega^(4))`
    D
    `ralpha`

    • Similar Questions

    Explore conceptually related problems

    In the sae figure. If v and omega both are constant, then find linear acceleration of point M,N,R and S in terms of R,omega,hati and hatj where R is the radius disc.

    A circular disc is rotating with an angular speed (in radian per sec) omega=2t^(2) given, CP=2m In terms of hati,hatj and hatk at t=1s find, (a). omega (b). alpha (c). linear velocity of the particle lying at P (d). linear acceleration of the particle lying P

    If angular velocity of a particle having position vector vec r = (2hati - 2hatj + 2hatk)m about the origin is vec w = (2hati - 2hatj - hatk)rad/s then magnitude of linear velocity of the particle will be

    A particle is given an initial velocity of vecu=(3 hati+4 hatj) m//s . Acceleration of the particle is veca=(3t^(2) +2 thatj) m//s^(2) . Find the velocity of particle at t=2s.

    if the displacement of the particle at an instant is given by y = r sin (omega t - theta) where r is amplitude of oscillation. omega is the angular velocity and -theta is the initial phase of the particle, then find the particle velocity and particle acceleration.

    If vecomega=2hati-3hatj+4hatk and vecr=2hati-3hatj+2hatk then the linear velocity is

    A charged particle enters a uniform magnetic field with velocity v_(0) = 4 m//s perpendicular to it, the length of magnetic field is x = ((sqrt(3))/(2)) R , where R is the radius of the circular path of the particle in the field. Find the magnitude of charge in velocity (in m/s) of the particle when it comes out of the field.

    Home
    Profile