A geostationary satellite is orbiting the earth at a height of `6R` above the surface oof earth where R is the radius of the earth .The time period of another satellite at a distance of `3.5R` from the centre of the earth is ….. hours.

Explanation

`T prop r^((3)/(2))` or
`:. (T_(2))/(T_(1)) = (r_(2)/(r_(1)))^(3/2)` or `T _(2) = (r_(2)/(r_(1)))^(3/2)T_(1)`
`T_(2) = ((3.5R)/(7R))^(3/2) (24)h = 8.48h` `(T_(1) = 24 h` for geostationary satellite)