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A source oscillates with a frequency 25 ...

A source oscillates with a frequency `25 Hz` and the wave propagates with `300m//s`. Two points `A` and `B` are located at distances `10m and 16m` away from the source. The phase difference between `A and B` is

A

`(pi)/(4)`

B

`(pi)/(2)`

C

`pi`

D

`2pi`

Text Solution

Verified by Experts

The correct Answer is:
C
`Deltaphi = (2pi)/(lambda)(Deltax) = (2pi phi(Deltax))/(v)`, (as `lambda = (v)/(f)`)
`=((2pi)(25)(16 - 10))/(300) =pi`
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