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34 g of H(2)O(2) is present in 1120 " mL...

34 g of `H_(2)O_(2)` is present in 1120 " mL of " solution. This solution is called

A

10 vol solution

B

20 vol solution

C

34 vol solution

D

32 vol solution

Text Solution

Verified by Experts

The correct Answer is:
A
`N=(W_(2)xx1000)/(Ew_(2)xxV_(mL))`
`N=(34xx1000)/(17xx1120)=(200)/(112)`
`1N of H_(2)O_(2)=5.6` volume strength.
`(200)/(112)N of H_(2)O_(2)=5.6xx(200)/(112)=10V`
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Knowledge Check

  • 34 g of H_(2)O_(2) is present in H_(2)O mL of solution. This solution is called.

    A
    `10 vol`
    B
    `20 vol`
    C
    `34 vol`
    D
    `32 vol`

  • 34 g of hydrogen peroxide is present in 1120 ml of Solution. This solution is called

    A
    10 volume
    B
    20 volume
    C
    30 volume
    D
    32 volume

  • 5.0 g of H_(2)O_(2) is present in 100 mL of the solution. The molecular mass of H_(2)O_(2) is 34. The molarity of the solution is :

    A
    1.5 M
    B
    0.15 M
    C
    3.0 M
    D
    50 M
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