Calculate osmotic pressure of a solution obtained by mixing `100 mL` of `3.4%` solution "(weight/volume)" of urea "(molecular weight 60)" and `100 mL` of `1.6%` solution "(weight/volume)" of cane sugar "(molecular weight 342)" at `20^(@)C`.

Explanation

`pi_(1)V_(1)=W_(1)/(Mw_1)RT_(1)` for urea
`pi_(2)V_(2)=W_(2)/(Mw_2)RT_(2)` for sugar
Since `100 mL` of urea solution is mixed with `100 mL` of cane sugar solution, and thus the total volume becomes `200 mL` in which `3.4 g` urea and `1.6 g` sugar is present.
`:.(pi_(1))xx200/1000=3.4/60 xx0.821 xx 293 =6.82` atm
`:.(pi_(2))xx200/1000=1.6/342 xx0.821 xx 293 =0.56` atm
`:.pi_("total")=pi_(1) + pi_(2)=6.82 + 0.56 = 7.38` atm