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Three masses are atteched to strings rot...

Three masses are atteched to strings rotaing in the horizontal plank .The string pass over two naine as shown in fig will this system be in equilibrium

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Considering the string over the left mail , the vertical components of the force of tension `T` acting on the weights are so the tension in the string above `O` is `T = 2 mg`
For the string on the right , the verticle component of the strings tension `T' is equal to `2 mg` (if the mass does not move down ) The tension of the along itself , however is `T = (2mg)/(cos theta) ge 2 mg` Therefore,the system is not in equalibrium .The right hand mass will have a greater pull.
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Knowledge Check

  • Two masses m and M are attached to the strings as shown in the figure. If the system is in equilibrium, then

    A
    `tantheta=1+(2M)/(m)`
    B
    `tantheta=1+(2m)/(M)`
    C
    `cottheta=1+(2M)/(m)`
    D
    `cottheta=1+(2m)/(M)`
  • Two masses m and M are attached with strings as shown. For the system to be in equilibrium we have.

    A
    `tantheta=1+(2M)/(m)`
    B
    `tantheta=1+(2m)/(M)`
    C
    `tantheta=1+(M)/(2m)`
    D
    `tantheta=1+(m)/(2M)`
  • Three equal weights of mass 2 kg each are hanging on a string passing over a fixed pulley as shown in fig What is the tension in the string connecting weights B and C?

    A
    zero
    B
    13 N
    C
    `3.3 N`
    D
    `19.6 N`
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