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A block is placed on an inclined plane m...

A block is placed on an inclined plane moving towards right horizontally with an acceleration `a_(0)=g`. The length of the plane `AC=1m`. Friction is absent everywhere. Find the time taken (in seconds) by the block to reach from C to A.

Text Solution

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The correct Answer is:
1
Drawing the free-body diagrame of block with respect to plane. Acceleraton of the block up the plane is
`a=(mg cos 37^(@)-mg sin 37^(@))/(m)`
`=g((4)/(5)-(3)/(5))=2ms^(-2)`
Applying , `s= (1)/(2) at^(2)` we get
`rArr r= sqrt((2s)/(a)) = sqrt((2 xx 1)/(2))=1s`
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Knowledge Check

  • A block is placed on an inclined plane moving towards right horizontally with an acceleration a_(0) = g . The length of the plane AC = 1m. Friction is absent everywhere. The time taken by the block to reach from C to A is : ( g = 10 m//s^(2))

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    1.2s
    B
    0.74 s
    C
    2.56 s
    D
    0.42 s

  • A block is placed on an inclined plane. The block is moving towards right horizontal with an acceleration a_(0)=g . The length of the inclined plane (AC) is equal to 1 m. Whole the situation are shown in the figure. Assume that all the surfaces are frictionless. The time taken by the block to reach from C to A is (Take, g=10m//s^(2) )

    A
    0.74 s
    B
    0.9 s
    C
    0.52 s
    D
    1.24 s

  • Block is placed on an inclined plane. The block is moving towards right horizontally with an acceleration a_(0) = g . The length of the inclined plane (AC) is equal to 1m. Whole the situation are shown in the figure. Assume that all the surfaces are frictionless. The time taken by the block to reach from to is ("take " g = 10 m // s^(2))

    A
    0.74 s
    B
    0.9 s
    C
    0.52 s
    D
    1.24 s

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