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Two soap bubbles A and B are kept in a c...

Two soap bubbles A and B are kept in a closed chamber where the air is maintained at pressure `8N//m^2`.The radii of bubbles A and B are 2cm and 4cm, respectively. Surface tension of the soap-water used to make bubbles is `0.04N//m`. Find tha ratio `n_B//n_A`, where `n_A` and `n_B` are the number of moles of air in bubbles A and B, respectively. [Neglect the effect of gravity.]

Text Solution

Verified by Experts

The correct Answer is:
6
`P_(A)=P_(0)+P_(A)=P_(0)+(4T)/R_(A)=16N//m^(2)`
`P_(B)=P_(0)+(4T)/R_(B)=12N//m^(2)`
`n_(B)//n_(A)=(P_(B))/(P_(A))((R_(B))/(R_(A)))^(3)=6`
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Two soap bubbles A and B are kept in a closed chamber where the air is maintained at pressure 8 N//m^(2) . The radii of bubbles A and B are 2 cm and 4 cm , respectively. Surface tension of the soap. Water used to make bubbles is 0.04 N//m . Find the ratio n_(B)//n_(A) , where n_(A) and n_(B) are the number of moles of air in bubbles A and B respectively. [Neglect the effect of gravity.]

Two soap bubbles A and B, of radii 2 cm and 4 cm, respectively , are in a closed chamber where air pressure is maintained at 8N/m^(2) . If n_(A) and n_(B) are the number of moles of air in bubbles A and B, respectively, then find the ratio n_(B) : n_(A) . [ Surface tension A soap solution = 0.04 N/m. Ignore the effect of gravity .

Knowledge Check

  • The radii of two soap bubbles are R_(1) and R_(2) respectively. The ratio of masses of air in them will be

    A
    `(R_(1)^(3))/(R_(2)^(3))`
    B
    `(R_(2)^(3))/(R_(1)^(3))`
    C
    `((P+(4T)/(R_(1)))/(P+(4T)/(R_(2))))(R_(1)^(3))/(R_(2)^(3))`
    D
    `((P+(4T)/(R_(2)))/(P+(4T)/(R_(1))))(R_(2)^(3))/(R_(1)^(3))`

  • The work done in blowing a soap bubble of 10 cm radius is (Surface tension of the soap solution is 3/100 N/m)

    A
    `75.36xx10^(-4) ` joule
    B
    `37.68xx10^(-4) ` joule
    C
    `150.72xx10^(-4)` joule
    D
    75.36 joule

  • The work done in increasing the radius of a soap bubble from 4 cm to 5 cm is Joule (given surface tension of soap water to be 25xx10^(-3)N//m)

    A
    `0.5657xx10^(-3)`
    B
    `5.657xx10^(-3)`
    C
    `56.5xx10^(-3)`
    D
    `565xx10^(-3)`

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