Home
Class 11
PHYSICS
A solid cylinder with r= 0.1 m and mass ...

A solid cylinder with `r= 0.1 m` and mass `M = 2 kg` is placed such that it is in contact with the vertical and a horizontal surface as shown in Fig. The coefficient of friction is `mu = (1//3)` for both the surfaces. Find the distance (in `CM`) from the centre of the cylinder at .which a force `F = 40 N` should be applied vertically so that the cylinder just starts rotating in anticlockwise direction.

Text Solution

Verified by Experts

The correct Answer is:
6

For equilibrium of the cylinder in the horizontal direction
`N_(1)=muN_(2)`……….i

In the vertical direction
`N_(2)+muN_(1)=F+mg`…….ii
Solving these two equations with `F=40N, M=2kg` and `mu=1/3`, we get
`N_(1)=18N`
and `N_(2)=54N`
Now, `Fd=mu(N_(1)+N_(1))r`
`:. d=(M(N_(1)+N_(2))r)/F`
`=((1/3)(18+50)(0.1))/40=0.06m`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • RIGID BODY DYNAMICS 1

    CENGAGE PHYSICS|Exercise Linked Comprehension|28 Videos
  • PROPERTIES OF SOLIDS AND FLUIDS

    CENGAGE PHYSICS|Exercise INTEGER_TYPE|2 Videos
  • RIGID BODY DYNAMICS 2

    CENGAGE PHYSICS|Exercise Interger|2 Videos

Similar Questions

Explore conceptually related problems

Two blocks of mass m_(1) and m_(2) (m_(2) gt m_(1)) are placed in contact with each other on an inclined plane as shown in figure . The coefficient of friction between m_(1) and surface is mu_(1) and between m_(2) and surface is mu_(2) .

A block mass m = 2 kg is accelerating by a force F = 20 N applied on a smooth light pully as shown in fig 7.86 If the coefficient of kinetic friction between the block and the surface is mu = 0.3 find its acceleration

Knowledge Check

  • A block of mass 1 kg is held at rest against a rough vertical surface by pushing by a force F horizontally. The coefficient of friction is 0.5. When

    A
    F = 40 N, friction on the block is 20 N.
    B
    F = 30 N, friction on the block is 10 N.
    C
    C = 20 N, friction on the block is 10 N.
    D
    Minimum value of force F to keep block at rest is 20 N.
  • A force F accelerates a block of mass m on horizontal surface. The coefficient of friction between the contact surface is . The acceleration of m will be -

    A
    `(F-mumg)/M`
    B
    zero
    C
    may be (A) or (B)
    D
    None of these
  • A horizontal force of 129.4 N is applied on a 10 kg block which rests on a horizontal surface. If the coefficient of friction is 0.3, the acceleration should be

    A
    `9.8m//s^(2)`
    B
    `10m//s^(2)`
    C
    `12.6m//s^(2)`
    D
    `19.6m/s^(2)`
  • Similar Questions

    Explore conceptually related problems

    A block of mass m = 2kg is accelerating by a force F = 20N applied on a smooth light pulley as shown in the figure. If the coefficient of kinetic friction between the block and the surface is mu=0.3 , find its acceleration.

    A block of mass 10kg is placed on a rough horizontal surface having coefficient of friction mu=0.5 . If a horizontal force of 100N is acting on it, then acceleration of the will be.

    A force of 100N is applied on a block of mass 3kg as shown in the figure. The coefficient of friction between the surface and the block is mu=(1)/(sqrt(3) . The friction force acting on the bock is.

    Two blocks of masses 1 kg and 2 kg are placed in contact on a smooth horizontal surface as shown in fig. A horizontal force of 6N is applied d(a) on a 1-kg block. Find the force of interaction of the blocks. .

    A mass m rests under the action of a force F as shown in the figure-2.158 on a horizontal surface. The coefficient of friction between the mass and the surface is mu . The force of friction between the mass and the surface is :