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The magnitude of a given vector with end...

The magnitude of a given vector with end points`(4, -4,0)` and `(-2, -2,0)` must be

A

6

B

`5sqrt(2)`

C

4

D

`2sqrt(10)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the magnitude of a vector defined by its endpoints, we can follow these steps: ### Step 1: Identify the endpoints of the vector The endpoints of the vector are given as: - Point A: \( (4, -4, 0) \) - Point B: \( (-2, -2, 0) \) ### Step 2: Determine the position vector The position vector \( \vec{r} \) from point A to point B can be calculated using the formula: \[ \vec{r} = \vec{r_2} - \vec{r_1} \] where \( \vec{r_1} = (4, -4, 0) \) and \( \vec{r_2} = (-2, -2, 0) \). ### Step 3: Calculate the components of the vector Calculating the components: \[ \vec{r} = (-2 - 4, -2 - (-4), 0 - 0) \] This simplifies to: \[ \vec{r} = (-6, 2, 0) \] ### Step 4: Calculate the magnitude of the vector The magnitude \( |\vec{r}| \) of the vector can be calculated using the formula: \[ |\vec{r}| = \sqrt{(x^2 + y^2 + z^2)} \] Substituting the components: \[ |\vec{r}| = \sqrt{(-6)^2 + (2)^2 + (0)^2} \] Calculating the squares: \[ |\vec{r}| = \sqrt{36 + 4 + 0} = \sqrt{40} \] ### Step 5: Simplify the magnitude We can simplify \( \sqrt{40} \): \[ |\vec{r}| = \sqrt{4 \times 10} = 2\sqrt{10} \] ### Final Answer The magnitude of the vector is: \[ |\vec{r}| = 2\sqrt{10} \] ---

To find the magnitude of a vector defined by its endpoints, we can follow these steps: ### Step 1: Identify the endpoints of the vector The endpoints of the vector are given as: - Point A: \( (4, -4, 0) \) - Point B: \( (-2, -2, 0) \) ### Step 2: Determine the position vector ...
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Knowledge Check

  • The points (-2,3,4), (1,1,2) and (4,-1,0) are

    A
    collinear
    B
    non-collinear
    C
    non-coplanar
    D
    non-collinear but coplanar
  • The equation of the ellipse passes through the points (4,0) and (0,2) is

    A
    `x^2/4+y^2/16=1`
    B
    `x^2/16+y^2/4=1`
    C
    `x^2/4+y^2/2=1`
    D
    `x^2/2+y^2/4=1`
  • The points (2, -1, -1), (4, -3, 0) and (0, 1, -2) are

    A
    collinear
    B
    non-coplanar
    C
    non-collinear
    D
    non-collinear and non-coplanar
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