What will be the force constant of the spring system shown in figure?

Options

A. `[(1)/(k_(1)) +(1)/(k_(2))]`
B. `[(1)/(2k_(1)) +(1)/(k_(2))]^(-1)`
C. `[(1)/(k_(1)) +(1)/(k_(2))]^(-1)`
D. `[(1)/(2k_(1)) +(1)/(k_(2))]`

Answer

B

Explanation

For parrallel combinacation of first two identical spring of spring constant `k_(1)` effactive spring constant
`K_(p) = 2k_(1)`
Now spring of spring constant `k_(p)` and `k_(2)` are joined in spring so the force constant of the spring constant of the system is
`(1)/(k_(s)) = (1)/(k_(p)) + (1)/(k_(2)) = ((1)/(2k_(1)) + (1)/(k_(2)))^(-1)`