A particle of mass `m` oscillates with simple harmonic motion between points `x_(1)` and `x_(2)` the equilibrium position being `O` its potential energy in plotted it will be as given bellow in the graph

Options

A.
B.
C.
D.

Answer

D

Explanation

Potential energy of particle performing `SHM` is given by `PE = (1)/(2) m omega^(2)y^(2)` i.e. veries parabolicalty such thet at mean position is become zero maximum at exterme position